Sine rule: finding an angle (ambiguous case): GCSE Practice
Non-Right Angled Trigonometry
Sine rule: finding an angle (ambiguous case)
4 self-marking GCSE and IGCSE practice questions on Sine rule: finding an angle (ambiguous case), written specifically for AQA, Pearson, OCR, Pearson International GCSE Maths A (4MA1), Cambridge IGCSE Mathematics (0580), Cambridge IGCSE (9-1) Mathematics (0980) across Higher and Extended tier. Instant marking with full worked solutions on every question.
Sample Sine rule: finding an angle (ambiguous case) questions
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Question 13 marksGrade 8-9
In triangle ABC, angle A = 40°, side a = 6.1 cm (opposite angle A), and side b = 7.4 cm (opposite angle B).
Find angle B, correct to 1 decimal place. This triangle has two possible cases - give both possible values of angle B.
What are the common mistakes in Sine rule: finding an angle (ambiguous case)?
When a pupil makes one of these on Revision Workshop, the marking engine names the mistake and explains it, instead of just marking the answer wrong.
Finds only one valid solution in an ambiguous-case (e.g. sine rule) situation where a second solution also exists
Only found the acute-angle solution from sin−1 - since angle A is acute and a<b but a>bsinA
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There are 4 self-marking GCSE and IGCSE Maths questions on Sine rule: finding an angle (ambiguous case), written for AQA, Pearson, OCR, Pearson International GCSE Maths A (4MA1), Cambridge IGCSE Mathematics (0580), Cambridge IGCSE (9-1) Mathematics (0980) across Higher and Extended tier. Each one is marked instantly and has a full worked solution.
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Show the worked solution
7.4sinB=6.1sin40°
sinB=6.17.4×sin40°, so B=51.2° (to 1 d.p.) M1 (1 correct answer)
Since angle A is acute and side a<b but a>bsinA, a SECOND triangle is also possible: the obtuse supplement B=180°−51.2°=128.8°
Check: both A+51.2° and A+128.8° are less than 180°, so both triangles are valid. Both values of angle B must be given. A1 (both correct answers)