Velocity vectors and kinematics: Additional Maths Practice
Vectors in Two Dimensions
Velocity vectors and kinematics
4 self-marking Additional Maths practice questions on Velocity vectors and kinematics, written specifically for Cambridge IGCSE Additional Maths (0606) across Single tier. Instant marking with full worked solutions on every question.
A few of the 4 questions, from easier to harder. Choose your exam board and tier to practise them, with every answer marked.
Question 12 marksGrade 7
A boat has a velocity of (43) km/h relative to the water. The water itself has a current velocity of (−12)
What are the common mistakes in Velocity vectors and kinematics?
When a pupil makes one of these on Revision Workshop, the marking engine names the mistake and explains it, instead of just marking the answer wrong.
Adds a rate quantity (e.g. velocity) once instead of scaling it by the elapsed time or other multiplier before adding
Position after time t is start position+t×velocity - the velocity must be scaled by the number of SECONDS (4) before adding, not added just once.
When finding where two moving objects meet, equates only their starting positions instead of the full time-dependent position expressions for every coordinate.
Quick answers about Velocity vectors and kinematics
How many Velocity vectors and kinematics practice questions are there?
There are 4 self-marking Additional Maths Maths questions on Velocity vectors and kinematics, written for Cambridge IGCSE Additional Maths (0606) across Single tier. Each one is marked instantly and has a full worked solution.
Do I need an account to practise Velocity vectors and kinematics?
No. You can start practising Velocity vectors and kinematics straight away without an account. A free account keeps your results across sessions, so you can see your progress on this topic over time.
km/h.
Find the resultant velocity of the boat relative to the ground. [2]
Show the worked solution
Resultant velocity =(43)+(−12)=(4+(−1)3+2)=(35) km/h.
Question 22 marksGrade 8
A particle starts at position (25) with constant velocity (3−1) m/s.
Find its position after 4 seconds. [2]
Show the worked solution
Position after 4 seconds =(25)+4(3−1)=(2+125−4)=(141)
Question 33 marksGrade 9
A ship sails at a speed of 20 km/h on a bearing of 060∘.
Express its velocity as a column vector, giving each component correct to 3 significant figures. [3]
Question 45 marksGrade 9
Particle P starts at the origin with velocity (32) m/s. Particle Q starts at position (100) with velocity (−22) m/s.
Show that P and Q collide, stating the time at which they collide. [5]
Collision requires both the x- AND y-coordinates of P and Q to match at the SAME time t - the equation needs the full time-dependent expressions 3t=10−2t, not just the particles' starting x-coordinates.
Subtracts a contributing velocity vector instead of adding it when finding a resultant velocity
The resultant (actual) velocity relative to the ground is the SUM of the boat's own velocity and the current's velocity, not their difference - the current pushes the boat along, it doesn't cancel its motion.