Home / Browse topics / Circle chord and tangent properties Circle chord and tangent properties
Circle chord and tangent properties 5 self-marking practice questions on Circle chord and tangent properties, written specifically for Pearson International GCSE Maths A (4MA1), Cambridge IGCSE Mathematics (0580), Cambridge IGCSE (9-1) Mathematics (0980) across Foundation and Higher and Extended tier. Instant marking with full worked solutions on every question.
Start practising Circle chord and tangent properties — no account needed Sample Circle chord and tangent properties questions A few of the 5 questions, from easier to harder. Choose your exam board and tier to practise them, with every answer marked.
Question 1 3 marks Grade 6
A B AB A B is a chord of a circle with centre O O O and radius 13 cm 13\text{ cm} 13 cm . A B = 24 cm AB = 24\text{ cm} A B = 24 cm . M M M is the midpoint of A B AB A B .
Work out the distance O M OM O M . [3] Show the worked solution The line from the centre perpendicular to a chord bisects the chord, so M B = 12 cm MB = 12\text{ cm} M B = 12 cm . M1 In right-angled triangle O M B OMB O M B : O M 2 = 13 2 − 12 2 = 25 OM^2 = 13^2 - 12^2 = 25 O M 2 = 1 3 2 − 1 2 2 = 25 Question 2 3 marks Grade 6
A B AB A B and C D CD C D are chords of a circle with centre O O O . A B = C D = 16 cm AB = CD = 16\text{ cm} A B = C D = 16 cm Question 3 3 marks Grade 6
P A PA P A and P B PB P B are tangents from the point P P P to a circle with centre O O O . The radius of the circle is 5 cm 5\text{ cm} 5 cm and O P = 13 cm OP = 13\text{ cm} O P = 13 cm Question 4 3 marks Grade 8
P A B PAB P A B and P C D PCD P C D are straight lines. The points A A A , B B B , C C C and D D D Practise all 5 questions on Circle chord and tangent properties Common mistakes in Circle chord and tangent properties When a pupil makes one of these on Revision Workshop, the marking engine names the mistake and explains it, instead of just marking the answer wrong.
Adds instead of pythagoras
Added 8 and 6. The radius is the hypotenuse of the right-angled triangle with sides 8 and 6, so use Pythagoras' theorem.
Assumes tangent equals op
Gave the length of OP. OP is the hypotenuse; the tangent length PA is a shorter side.
Divides by a conversion factor where multiplying was needed
Worked out 6 ÷ 3 or 4 ÷ 2. The intersecting chords property multiplies: AP × PB = CP × PD.